VBA – DateDiff Function

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Difference function

A Function, which returns the difference between two specified time intervals.

Syntax

DateDiff(interval, date1, date2 [,firstdayofweek[, firstweekofyear]]) 

Parameter Description

  • Interval − A required parameter. It can take the following values.
    • d – day of the year
    • m – month of the year
    • y – year of the year
    • yyyy – year
    • w – weekday
    • ww – week
    • q – quarter
    • h – hour
    • m – minute
    • s – second
  • Date1 and Date2 − Required parameters.
  • Firstdayofweek − An optional parameter. Specifies the first day of the week. It can take the following values.
    • 0 = vbUseSystemDayOfWeek – Use National Language Support (NLS) API setting
    • 1 = vbSunday – Sunday
    • 2 = vbMonday – Monday
    • 3 = vbTuesday – Tuesday
    • 4 = vbWednesday – Wednesday
    • 5 = vbThursday – Thursday
    • 6 = vbFriday – Friday
    • 7 = vbSaturday – Saturday
  • Firstdayofyear − An optional parameter. Specifies the first day of the year. It can take the following values.
    • 0 = vbUseSystem – Use National Language Support (NLS) API setting
    • 1 = vbFirstJan1 – Start with the week in which January 1 occurs (default)
    • 2 = vbFirstFourDays – Start with the week that has at least four days in the new year
    • 3 = vbFirstFullWeek – Start with the first full week of the new year

Example

Add a button and add the following function.

Private Sub Constant_demo_Click()
   Dim fromDate as Variant
   fromDate = "01-Jan-09 00:00:00"
   
   Dim toDate as Variant
   toDate = "01-Jan-10 23:59:00"
   
   msgbox("Line 1 : " &DateDiff("yyyy",fromDate,toDate))
   msgbox("Line 2 : " &DateDiff("q",fromDate,toDate))
   msgbox("Line 3 : " &DateDiff("m",fromDate,toDate))
   msgbox("Line 4 : " &DateDiff("y",fromDate,toDate))
   msgbox("Line 5 : " &DateDiff("d",fromDate,toDate))
   msgbox("Line 6 : " &DateDiff("w",fromDate,toDate))
   msgbox("Line 7 : " &DateDiff("ww",fromDate,toDate))
   msgbox("Line 8 : " &DateDiff("h",fromDate,toDate))
   msgbox("Line 9 : " &DateDiff("n",fromDate,toDate))
   msgbox("Line 10 : "&DateDiff("s",fromDate,toDate))
End Sub

When you execute the above function, it produces the following output.

Line 1 : 1
Line 2 : 4
Line 3 : 12
Line 4 : 365
Line 5 : 365
Line 6 : 52
Line 7 : 52
Line 8 : 8783
Line 9 : 527039
Line 10 : 31622340

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