A return C# Passing Parameters by Output function. However, using output parameters, you can return two values from a function. Output parameters are similar to reference parameters, except that they transfer data out of the method rather than into it.
The following example illustrates this −
using System;
namespace CalculatorApplication {
class NumberManipulator {
public void getValue(out int x ) {
int temp = 5;
x = temp;
}
static void Main(string[] args) {
NumberManipulator n = new NumberManipulator();
/* local variable definition */
int a = 100;
Console.WriteLine("Before method call, value of a : {0}", a);
/* calling a function to get the value */
n.getValue(out a);
Console.WriteLine("After method call, value of a : {0}", a);
Console.ReadLine();
}
}
}
The following result −
Before method call, value of a : 100 After method call, value of a : 5
Output parameters are particularly useful when you need to return values from a method through the parameters without assigning an initial value to the parameter. Go through the following example, to understand this −
using System;
namespace CalculatorApplication {
class NumberManipulator {
public void getValues(out int x, out int y ) {
Console.WriteLine("Enter the first value: ");
x = Convert.ToInt32(Console.ReadLine());
Console.WriteLine("Enter the second value: ");
y = Convert.ToInt32(Console.ReadLine());
}
static void Main(string[] args) {
NumberManipulator n = new NumberManipulator();
/* local variable definition */
int a , b;
/* calling a function to get the values */
n.getValues(out a, out b);
Console.WriteLine("After method call, value of a : {0}", a);
Console.WriteLine("After method call, value of b : {0}", b);
Console.ReadLine();
}
}
}
The following result −
Enter the first value: 7 Enter the second value: 8 After method call, value of a : 7 After method call, value of b : 8
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