This topic is about Go – Call by reference.
The call by reference method of passing arguments to a function copies the address of an argument into the formal parameter. Inside the function, the address is used to access the actual argument used in the call. This means that changes made to the parameter affect the passed argument.
To pass the value by reference, argument pointers are passed to the functions just like any other value. Accordingly you need to declare the function parameters as pointer types as in the following function swap(), which exchanges the values of the two integer variables pointed to by its arguments.
/* function definition to swap the values */
func swap(x *int, y *int) {
var temp int
temp = *x /* save the value at address x */
*x = *y /* put y into x */
*y = temp /* put temp into y */
}
For now, let us call the function swap() by passing values by reference as in the following example
package main
import "fmt"
func main() {
/* local variable definition */
var a int = 100
var b int = 200
fmt.Printf("Before swap, value of a : %d\n", a )
fmt.Printf("Before swap, value of b : %d\n", b )
/* calling a function to swap the values.
* &a indicates pointer to a ie. address of variable a and
* &b indicates pointer to b ie. address of variable b.
*/
swap(&a, &b)
fmt.Printf("After swap, value of a : %d\n", a )
fmt.Printf("After swap, value of b : %d\n", b )
}
func swap(x *int, y *int) {
var temp int
temp = *x /* save the value at address x */
*x = *y /* put y into x */
*y = temp /* put temp into y */
}
Put the above code in a single Go file, and then compile and execute it. It produces the following result −
Before swap, value of a :100 Before swap, value of b :200 After swap, value of a :200 After swap, value of b :100
It shows that the change has reflected outside the function as well, unlike call by value where the changes do not reflect outside the function.
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